Question

Решите уравнение 3х+1=√1-х

Answer 1

$3x+1= \sqrt{1-x}$
$( 3x+1)^{2} =1-x$
$9 x^{2} +6x+1=1-x$
$9 x^{2} +7x=0$
$x(9x+7)=0$
$x1=0$
$9X+7=0$
$x2=- \frac{7}{9}$

Answer 2

(3х+1)^2=1-х
9х^2+6х+1-1+х=0
9х^2+7х=0
х(9х+7)=0
х1=0
9х+7=0
9х=-7
х=-7/9