Question

0.25lg^2 4+lg2*lg25+lg^2 0.2

Answer 1

$0,25lg^24+lg2*lg25+lg^20,2=\\\\=(0,5lg4)^2+lg2*lg5^2+(lg5^{-1})^2=\\\\=lg^2 \sqrt{4}+2lg2*lg5+lg^25=\\\\=lg^22+2lg2*lg5+lg^25=\\\\=(lg2+lg5)^2=(lg10)^2=1^2=1$