Question

Вычислите :
а) 2^12 -2^9
----------------
7 * 2^8


в) 3^12 + 3^10
_____________
3^8

Answer 1

$\frac{2^{12} -2^{9}}{7\cdot 2^{8}}=\frac{2^{9}(2^{3} -1)}{7\cdot 2^{8}}=\frac{2^{9}(8 -1)}{7\cdot 2^{8}}=2 \\ \\ \frac{3^{12} + 3^{10}}{3^{8}}= \frac{3^{10}(3^{2} +1)}{3^{8}}=3^2\cdot(9+1)=90$