Предмет: Химия, автор: iosifdovbush

выведите формулу алкина содержащего 88.24%

углевода 11.11%

Ответы

Автор ответа: kattycats
1
CnH2n-2
n : (n-2) = 88.24/12 : 11.11/1 = 7,35 : 11.11 = 1 : 1.5 = 2 : 3, следовательно, n = 2, получаем формулу C2H2 
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