Question

решите уравнение (x-3)²=10x²-(3x-4)(3x+4)
срочно

Answer 1

x^2 - 6x + 9 = 10x^2 -(9x^2 - 16)
x ^2 - 6x + 9 = 10x^2 - 9x^2 + 16
x ^2 - x^2 - 6x = -9 +16
-6x = 7
   x = - 1 1/6

Answer 2

$(x-3)^2=10x^2-(3x-4)(3x+4) \\ x^2-6x+9=10x^2-(9x^2-16) \\ x^2-6x+9=10x^2-9x^2+16 \\ x^2-10x^2+9x^2-6x=16-9 \\ -6x=7 \\ x=-1 \frac{1}{6}$