Question

Решите систему уравнений.
{ 3x-2у=16
x+4у=-4

{ 4x-у-24=2(5x-29)
3у-2=4-(x-у)

Answer 1

1){ 3x-2у=16/*2⇒6x-4y=32
x+4у=-4
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7x=28
x=4
4+4y=-4
4y=-8
y=-2(4;-2)
2)
{ 4x-у-24=2(5x-29)⇒4x-10x-y=-58+24⇒-6x-y=-34/*2⇒-12x-2y=-68
3у-2=4-(x-у) ⇒3y+x-y=4+2⇒x+2y=6
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-11x=-62
x=62/11
62/11+2y=6
2y=6-62/11=4/11
y=2/11
(62/11;2/11)