Предмет: Алгебра, автор: киска5а

Очень нужна ваша помощь, желательно срочно, фото снизу..
Заранее вам благодарна! ^_^

(Контрольные вопросы)

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Автор ответа: bordukovak

решила методом подстановки .

Приложения:

Автор ответа: ivanovayana20

1. 1)у=2х-7
2) х²-х(2х-7)=12
х²-2х²+7х=12
х²-7х+12=0
D=49-4·12=1
х1= $\frac{7-1}{2}$ =3
х2= $\frac{7+1}{2}$ =4
у1=2·3-7=-1
у2=2·4-7=1
Ответ. (3;-1),(4;1)

2. 4х-3у=-1 вычитаем 4х+10у=12 ⇒-13у=-13 | ÷(-13)
у=1
4х=-2 | ÷4
х=-0,5
Ответ. (-0,5;1)

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