Question

0.3(3x-1)+0.2=5(0.1-0.2x)-0.1

Answer 1

$0.3(3x-1)+0.2=5(0.1-0.2x)-0.1$
$0.9x-0.3+0.2=0.5-x-0.1$
$0.9x-0.1=0.4-x$
$0.9x-x=0.1-0.4$
$-0.1x=-0.7$
$x=7$