Question

(8x^3+1)/(2x-1)*(4x^2-4x+1)/(4x^2-2x+1)

Answer 1

$\sf \dfrac{8x^3+1}{2x-1}\cdot\dfrac{4x^2-4x+1}{4x^2-2x+1}=\dfrac{(2x+1)(4x^2-2x+1)}{2x-1}\cdot\dfrac{(2x-1)^2}{4x^2-2x+1}=\\\\\\ \sf =(2x+1)(2x-1)=(2x)^2-1^2=\bold{4x^2-1}$