Question

1 целая 9/40 * (7 целых 5/7 : 3 целых 3/5 - (53/56 - 29/35) : 33/40)=???!!!!

Answer 1

$1) \frac{53}{56} - \frac{29}{35} = \frac{265-232}{280} = \frac{33}{280} \\ 2) \frac{33}{280} : \frac{33}{40}= \frac{33}{280} * \frac{40}{33}= \frac{1}{7} \\ 3)7 \frac{5}{7}:3 \frac{3}{5} = \frac{54}{7}: \frac{18}{5} = \frac{54}{7} * \frac{5}{18} = \frac{15}{7} \\ 4) \frac{15}{7} - \frac{1}{7}= \frac{14}{7} =2 \\ 5)1 \frac{9}{40} *2= \frac{49}{40} *2= \frac{49}{20} =2 \frac{9}{20}$