Question

РЕШИТЕ СИСТЕМУ УРАВНЕНИЙ

Answer 1

$\left \{ {{x+y=2} \atop {2x^{2}+xy+y^{2}=8}} \right. \\ \left \{ {{x=2-y} \atop {2x^{2}+xy+y^{2}=8}} \right. \\ 2(2-y)^{2}+(2-y)y+y^{2}=8 \\ 2(4-4y+y^{2})+2y-y^{2}+y^{2}=8 \\ 8-8y+2y^{2}+2y=8 \\ -6y+2y^{2}=0 \\ 2y(2y-3)=0 \\ y=0 \\ y= 3 \\ x(0)=2 \\ x(3) = -1$
Ответ (-1;3) (2;0)