Question

Вариант 3 , задание 3, заранее спасибо

Answer 1

$left { {{x+y=frac{pi}{2}} atop {sin x+sin y=-sqrt{2}}} right;\ left { {{y=frac{pi}{2}-x} atop {sin x+sin y=-sqrt{2}}} right;\ left { {{y=frac{pi}{2}-x} atop {sin x+sin (frac{pi}{2}-x)=-sqrt{2}}} right;\ left { {{y=frac{pi}{2}-x} atop {sin x+cosx=-sqrt{2}}} right;\ left { {{y=frac{pi}{2}-x} atop {sqrt{2}(frac{1}{sqrt{2}}sin x+frac{1}{sqrt{2}}cosx)=-sqrt{2}}} right;$

$left { {{y=frac{pi}{2}-x} atop {sqrt{2}(sin xcosfrac{pi}{4}+cos xsinfrac{pi}{4})}=-sqrt{2}}} right;\ left { {{y=frac{pi}{2}-x} atop {sqrt{2}sin (x+frac{pi}{4})}=-sqrt{2}}} right;\ left { {{y=frac{pi}{2}-x} atop {sin (x+frac{pi}{4})}=-1} right;\ left { {{y=frac{pi}{2}-x} atop {x+frac{pi}{4}}=-frac{pi}{2}+2*pi*k} right;\ left { {{y=frac{pi}{2}-x} atop {x=-frac{3pi}{4}+2*pi*k} right;$

$left { {y=frac{5pi}{4}-2 *pi*k} atop {x=-frac{3pi}{4}+2*pi*k} right;\ left { {y=frac{-3pi}{4}-2 *pi*k} atop {x=-frac{3pi}{4}+2*pi*k} right;$