Question

Помогите пожалуйста решить премеры:
1/2m-8m+3m;
x/3-x/2+x/6;
5/6z-1,3/4z+13/18z

Answer 1

$\frac{1}{2m} -8m+3m= \frac{1-16m^{2} +6 m^{2} }{2m} = \frac{ 1 - 22m^{2} }{2m}  [tex] \frac{x}{3} - \frac{x}{2} + \frac{x}{6} = \frac{2x-3x+x}{6} = \frac{1}{6}$

$\frac{5}{6z} - \frac{1,3}{4z} + \frac{13}{18z} = \frac{30-11,7+26}{36z} = \frac{44,3}{36z} =1 \frac{8,3}{36z}$