Question

tg^2-sin^2-tg^2sin^2 упростите выражение

Answer 1

tg²α - sin²α - tg²αsin²α = tg²α - tg²αsin²α - sin²α = tg²α(1 - sin²α) - sin²α =

=tg²αcos²α - sin²α = $\frac{sin ^{2} \alpha }{cos ^{2} \alpha } cos ^{2} \alpha -sin ^{2} \alpha =sin ^{2} \alpha -sin ^{2} \alpha =0$