Question

Решите уравнение (4-x)^2+(x-3)^2=2x^2+4

Answer 1

$(4-x)^{2}+(x-3)^{2}=2x^{2}+4 \\ 16 - 8x + x^{2} + x^{2} -6x+9-2x^{2} = 4 \\ -14x+25=4 \\ -14x = 4-25 \\ -14x = -21 \\ x = \frac{-21}{-14} \\ x = \frac{3}{2} \\ x=1,5$

Answer 2

(4-x)²+(x-3)²=2x²+4
16-8x+x²+x²-6x+9-2x²-4=0
-14x+21=0
14x=21
x=21/14=3/2=1 1/2