Предмет: Геометрия, автор: Chloe12

50 баллов.
В прямоугольном треугольнике катет, прилежащий к углу 30 градусов, равен 48 см. Найдите длину биссектрисы другого острого угла.
С рисунком, дано, и решением (очень желательно, на 50 баллов думаю очень даже), но если знаете хотя бы одно - добро пожаловать :D
В случае "ой, мне нужны баллы" ответ будет удален, и баллов вы все равно не получите.

Chloe12: Прошу прощения, я учусь в 7 классе, и мы даже не учили теорему Пифагора)

Ответы

Автор ответа: LFP

15

катет, лежащий против угла в 30 градусов = половине гипотенузы))
сумма острых углов прямоугольного треугольника = 90 градусов
второй острый угол будет = 60 градусов
и биссектриса разделит его на два угла по 30 градусов...

Приложения:

Chloe12: тоже так думала, но все это слишком просто.
тем более, не просто же 48 см в задаче валяется

LFP: оно не "валяется", оно главное действующее "лицо" задачи...

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