Предмет: Физика, автор: snegovik66

Помогите решить задачку! при включении магнитофона в сеть с напряжением 220 В, через его сеть прошел заряд 2500 Кл, чему равна А тока в цепи?

Ответы

Автор ответа: Аноним

U - напряжение ( 220 В )
q - заряд ( 2500 Кл )
А - работа тока ( ? )

А = U * q = 2500 Кл * 220 В = 550 000 Дж = 550 кДж

Ответ : 550 кДж

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