Question

номер 578 решите плиззз

Answer 1

$(m+1- \frac{1}{1-m} ):(m- \frac{m^2}{m-1} )=(m+1- \frac{1}{1-m} )( \frac{1}{m}- \frac{m-1}{m^2})$

$m*(- \frac{m-1}{m^2})+ m* \frac{1}{m} +m- \frac{m-1}{m^2} - \frac{1}{1-m} * \frac{1}{m} + \frac{1}{1-m} * \frac{m-1}{m^2} =$

$1+1+m- \frac{-1}{m} - \frac{1}{m2} + \frac{1}{m^2} =2+m+ \frac{1}{m}$