Предмет: Алгебра, автор: Аня113

а)(2x-5)^2-(2x-3)(2x+3)=0
б)9y^2-25=0
РЕШИТЕ УРАВНЕНИЕ,ЗАРАНЕЕ СПАСИБО :)

Ответы

Автор ответа: eVa74
1
4x²-20x+25-4x²+9=0
-20x-11=0
-20x=-34
x=1.7

(3x-5)(3x+5)=0
9(x-5/3)(x+5/3)=0
x1=5/3
x2=-5/3
konya96: почему 11? в первом примере
konya96: вы ошиблись
eVa74: согласна не туда глянула
eVa74: во втором задании должно получиться два корня + -
konya96: вы правы
Автор ответа: konya96
2
1)(2x-5)^2-((2x)^2-3^2)=0 
4x^2-20x+25-4x^2+9=0
-20x=-25-9
x=1,7

2) 9y^2=25
(3y)^2=25
3y=корень из 25
3y=5
y=+-5/3
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