Question

Решите уравнение
7(x2+2x-2)=(1-x)(1+x)

Answer 1

$7( x^{2} +2x-2)=(1-x)(1+x) \\ 7 x^{2} +14x-14= 1-x^{2} \\ 7 x^{2} +14x-14-1+ x^{2} =0\\8 x^{2} -14x-15=0\\D=196+480=676\\ \sqrt{D} =26 \\ x_{1} = \frac{14+26}{16} = \frac{40}{16} =2.5\\x_{1} = \frac{14-26}{16} = \frac{-12}{16} =-0.75$

Answer 2

2x(4x+7)=15
8x2+14x-15=0
7(x(x+2)-2)=1-x2
7x2+14x-14=1-x2
x=-5/2 (дробью записать)
x=3/4 (дробью записать)