Question

сократить дробь 9p^2-q^2/9p^2+6pq+q^2

Answer 1

$\frac{9p ^{2} -q ^{2} }{9p ^{2}+6pq+q ^{2} } = \frac{(3p-q)(3p+q)}{(3p+q) ^{2} } = \frac{3p-q}{3p+q}$