Question

2sinx-корень из3=0

ctg x3 -1 =0

соs(2x -пи3)=-1

Answer 1

$2sinx - sqrt{3} = 0 \ \ sinx = dfrac{ sqrt{3} }{2} \ \ boxed{ x = (-1)^{n} dfrac{ pi }{3} + pi n, n in Z}$


$ctg dfrac{x}{3} -1 = 0 \ \ ctg dfrac{x}{3} = 1 \ \ dfrac{x}{3} = dfrac{pi }{4} + pi n, n in Z \ \ boxed{x = dfrac{3pi }{4} + 3 pi n, n in Z}$


$cos(2x - dfrac{ pi }{3}) = -1 \ \ 2x - dfrac{ pi }{3} = pi + 2 pi n, n in Z \ \ 2x = dfrac{4 pi }{3} + 2 pi n, n in Z \ \ boxed{ x = dfrac{2 pi }{3} + pi n, n in Z}$