Question

$tg \frac{20 \pi }{3} =$

$tg \frac{28 \pi }{3} =$

$tg(- \frac{31 \pi }{6} )=$

$ctg \frac{16 \pi }{3}$

Answer 1

tg$\frac{20*pi}{3}$=tg(7π-$\frac{pi}{3}$) =-tg$\frac{pi}{3}$=-√3

tg$\frac{28*pi}{3}$=tg(9π+$\frac{pi}{3}$) =tg$\frac{pi}{3}$=√3

tg(-$\frac{31*pi}{6}$)=-tg$\frac{31*pi}{6}$=-tg(5π+$\frac{pi}{6}$)=-tg$\frac{pi}{6}$=-$\frac{1}{ \sqrt{3} }$

ctg$\frac{16*pi}{3}$=ctg(5π+$\frac{pi}{3}$)=ctg$\frac{pi}{3}$=$\frac{1}{ \sqrt{3} }$