Question

помогити пожайлусто ришить по действием

Answer 1

$a)\;\frac{\left(\frac34-\frac12\right):\frac57}{\left(\frac14+\frac23\right):\frac6{11}}\\1)\;\frac34-\frac12=\frac34-\frac24=\frac14\\2)\;\frac14:\frac57=\frac14\cdot\frac75=\frac7{20}\\3)\;\frac14+\frac23=\frac3{12}+\frac8{12}=\frac{11}{12}\\4)\;\frac{11}{12}\cdot\frac6{11}=\frac6{12}=\frac12\\\frac7{20}:\frac12=\frac7{20}\cdot2=\frac7{10}\\\frac{\left(\frac34-\frac12\right):\frac57}{\left(\frac14+\frac23\right):\frac6{11}}=\frac7{10}$

$b)\;\frac{\frac3{20}\cdot\left(\frac7{12}-\frac12\right)+\frac{79}{80}}{\frac{13}{24}:\left(\frac7{12}+\frac12\right)-\frac14}\\1)\;\frac7{12}-\frac12=\frac7{12}-\frac6{12}=\frac1{12}\\2)\;\frac3{20}\cdot\frac1{12}=\frac3{240}\\3)\;\frac3{240}+\frac{79}{80}=\frac3{240}+\frac{237}{240}=\frac{240}{240}=1\\4)\;\frac7{12}+\frac12=\frac7{12}+\frac6{12}=\frac{13}{12}\\5)\;\frac{13}{24}:\frac{13}{12}=\frac{13}{24}\cdot\frac{12}{13}=\frac12$
$6)\;\frac12-\frac14=\frac24-\frac14=\frac14\\7)\;1:\frac14=1\cdot\frac41=4$