Question

1) в
2)з
помогите пожалуйста

Answer 1

1B)    ... =√4*√4 +∛8 : (2/(-5)³ : 3³ =2*2+2:(-8/125):27 = 4 -125/4:27=
=4 -125/108 =307/432 .

2з) (81^(2 + Log(1/2)(1/ 3)*Log(1/3)(4 )  :((2+(√3)^Loq(3)(1/16))^Loq(9/4) (3) =
= (81^(2 +Loq(1/2) 4) : :((2+ 3)^(Loq(3)(1/4))^  Loq(9/4) (3) =:
=81^(2 -2) : (2+1/4)^Loq(9/4) (3) =81^0 :(9/4)^Loq(9/4)(3)  =81^0 :3  =1/3.