Question

$(x-10)^2=(2-x)^2$

Answer 1

$(x-10)^{2} =(2-x)^{2} \\ \\ (x-10)^{2} -(x-2)^{2} =0 \\ \\ (x-10-(x-2))(x-10+x-2)=0 \\ \\ (x-10-x+2)(2x-12)=0 \\ \\ -8*2(x-6)=0 \\ \\ x-6=0 \\ \\ x=6$