Question

1.7.15 решите срооочноооо!!!!

Answer 1

$\frac{(x^2-y^2)^2}{x^2+2xy+y^2}:(\frac{1}{x^2}-\frac{1}{y^2})=\frac{(x-y)^2(x+y)^2}{(x+y)^2}:\frac{y^2-x^2}{x^2y^2}=\\\\=(x-y)^2\cdot \frac{x^2y^2}{(y-x)(y+x)}=-\frac{(x-y)x^2y^2}{y+x}$