Question

Найти производную!
f'(x)=x^3-3x/1+4x^5

f'(x)=5-2x^6/1-x^3

Answer 1

$f(x)=\frac{x^3-3x}{1+4x^5}\\\\y'=\frac{(3x^2-3)(1+4x^5)-(x^3-3x)\cdot 20x^4}{(1+4x^5)^2}\\\\\\y=\frac{5-2x^6}{1-x^3}\\\\y'==\frac{-12x^5(1-x^3)-(5-2x^6)(-3x^2)}{(1-x^3)^2}$