Question

Cократите указанные дроби

Answer 1

Решение в приложении////////////////////////////

Answer 2

(a-a²)/(a²-1)=a(1-a)/(a-1)(a+1)=-a/(a+1)
(a²-1)/(1-a)=(a-1)(a+1)/(1-a)=-(a+1)
(m-n)/(n-m)²=(m-n)/(m-n)²=1/(m-n)
(a²+2ab+b²)/(a²-b²)=(a+b)²/(a-b)(a+b)=(a+b)/(a-b)
(x²-2x+1)/(x²-1)=(x-1)²/(x-1)(x+1)=(x-1)/(x+1)
(3a²-6ab+3b²)/(6a²-6b²)=3(a-b)²/6(a-b)(a+b)=(a-b)/2(a+b)