Question

Сократить дроби :
1) 5x-10/(x-2)^2
2) (n-3)^2/6-2n

Answer 1

$\frac{5x-10}{(x-2)^2}= \frac{5(x-2)}{(x-2)(x-2)}= \frac{5}{x-2} \\ \frac{(n-3)^2}{6-2n}= \frac{(3-n)^2}{2(3-n)}= \frac{3-n}{2}$