Question

найти значение выражения. sin²π÷13+cos²π÷13-(cos²π÷12-sin²π÷12)

Answer 1

sin²π÷13+cos²π÷13-(cos²π÷12-sin²π÷12)=1-(cos2π÷12)=1-(cosπ÷6)=1-корень(3)/2

Answer 2

$(\sin^2{\frac{\pi}{13}} + \cos^2{\frac{\pi}{13}}) - (\cos^2{\frac{\pi}{12}} - \sin^2{\frac{\pi}{12}}) = 1 - \cos{\frac{\pi}{6}} = \frac{2 - \sqrt{3}}{2}$