Question

√2x+10 +x+1=0 (x+1)не под корнем

Answer 1

$\sqrt{2x+10} +x+1=0 \\ \sqrt{2x+10} =-x-1 \\ (\sqrt{2x+10})^{2} =(-x-1)^{2} \\ 2x+10= x^{2} +2x+1 \\ x^{2} +2x-2x+1-10=0 \\ x^{2} -9=0 \\ x^{2} =9 \\ x=+-3 \\ \\ \sqrt{2*3+10} +3+1=0 \\ \sqrt{6+10} +3+1= \sqrt{16} +4=4+4=16 \\ 16 \neq 0$
$\\ \sqrt{2*(-3)+10} -3+1=0 \\ \sqrt{-6+10} -3+1= \sqrt{4} -2=2-2=0 \\ x=-3$

Ответ: х= -3