Question

найдите корни уравнения x^2\3-3=0

Answer 1

$\frac{x^2}{3}-3=0\\\frac{x^2}{3}=3\\x^2=3*3\\\sqrt{x^2}=\sqrt{3*3}\\|x|=3\\x=3\ \ \ \ ili\ \ \ \ x=-3$


если 2/3 в степени:
$x^\frac{2}{3}-3=0\\x^\frac{2}{3}=3\\(x^\frac{2}{3})^3=3^3\\x^2=3*3*3\\\sqrt{x^2}=\sqrt{3*3*3}\\|x|=3\sqrt{3}\\x=3\sqrt{3}\ \ \ \ ili\ \ \ \ x=-3\sqrt{3}$