Question

Решите уравнение х(х² + 2х +1) = 6(х + 1)

Answer 1

$x(x^2+2x+1)=6(x+1)\\ x(x+1)^2-6(x+1)=0\\(x+1)(x(x+1)-6)=0\\(x+1)(x^2+x-6)=0\\(x+1)(x-2)(x+3)=0\\x_1=-1;x_2=2;x_3=-3$