Предмет: Математика, автор: nurtilekooo

на рыбном заводе двое рабочих работали одинаковое время первый за это время почистил 48 рыбин по 12 рыбин в час сколько рыбин почистил за это время второй рабочий если он чистил по 18 рыбин в час

Ответы

Автор ответа: Аноним

6

1) 48 / 12 = 4 часа - работали рабочие.
2) 4 * 18 = 72 рыбины очистил второй рабочий.

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