Question

4sin п/6 * sin^2п/4 * tg^2п/3

Answer 1

$4sin\frac{\pi}{6}*sin^2\frac{\pi}{4}*tg^2\frac{\pi}{3}=4*\frac{1}{2}*(\frac{\sqrt{2}}{2})^2*(\sqrt3)^2=2*\frac{2}{4}*3=3$