Question

решите неравенство

  log1/3(2-3x)<-2

 

 

Answer 1

ОДЗ:
2-3х>0
3x<2
x<2/3

$log_{ frac{1}{3}}(2-3x) textless -2 \ \ log_{ 3^{-1}}(2-3x) textless -2 \ \ - log_{ 3}(2-3x) textless -2 \ \ log_{ 3}(2-3x) textgreater 2 \ \ 2-3x textgreater 3^2 \ \ 3x textless 2-9 \ \ 3x textless -7 \ \ x textless - frac{7}{3} \ \ x textless -2 frac{1}{3}$

x∈(-∞; -2  1/3)