Предмет: Геометрия, автор: NessiFromLochNis

пожалуйста помогите. задание в картинке

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Автор ответа: Fedor

угол ADC=180-120=60 градусов

угол CAD =90-60=30 градусов

Сторона лежащая напротив угла 30 градусов равна гипотенузе, то есть AD=12

Треугольник ADB - равнобедренный, с вершины D опустим на AB высоту DM

Угол ADM=120/2=60 градусов

угол DAM=90-60=30 градусов

DM=AD/2=6

Из треугольника ADM по теореме Пифагора

AM^2=AD^2-DM^2=144-36=108

AM=6*sqrt(3)

AM=MB =>AB=2*AM=12*sqrt(3)

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