Question

sin(-405°)+cos750°=
cos(-780°)-tg(-225°)=
sin2,5Π+ctg(-3/4Π)=
the(-7/6Π)-ctg10/3Π=

помогите решить...#

Answer 1

-sin(360+45)+cos(720+30)=-√2/2+√3/2=(-√2+√3)/2
cos(720+60)-tg(-180-45)=1/2+1=3/2
sin(2p+p/2)+ctg(-p+p/4)=1+1=2
tg(-p-p/6)-ctg(3p+p/3)=-√3/3-√3/3=-2√3/3