Question

log3 (5x+7) = log3 (7x+5)

Answer 1

$log_{3} (5x+7)=log_3(7x+5) \\ 5x+7=7x+5 \\ 2x=2 \\ x=1$

Answer 2

$\log_3(5x+7)=\log_3(7x+5);\\ 3^{\log_3(5x+7)}=3^{\log_3(7x+5)};\\ (5x+7)=(7x+5);\\ 5x+7=7x+5;\\ 7-5=7x-5x;\\ 2=2x;\\ x=1.$