Question

cos80°÷(cos40°+sin40°)

Answer 1

Cos 80/(cos 40+sin 40)=cos 2•40/(cos 40+sin40)=(Cos^2 40-sin^2 40)/(cos 40+sin 40)=(Cos 40-sin 40)(cos 40+sin 40)/(cos 40+sin 40)=cos 40-sin 40