Question

Найдите производную функции:
1) y=x^2 tgx
2) y=-1/x^3

Answer 1

$y=x^2\cdot tgx\\\\y'=2x\cdot tgx+x^2\cdot \frac{1}{cos^2x}\\\\\\y=-\frac{1}{x^3}=-x^{-3}\\\\y'=-(-3)\cdot x^{-2}=\frac{3}{x^2}$