Question

Найдите производную функции

y=2x^3-x^2/2+4

y=2cosx-3tgx

y=(x-3)/(x+2)

Answer 1

$y'=(2x^3-\frac{x^2}{2}+4)'=2*3x^2-\frac{2x^1}{2}+0=6x^2-x\\\\y'=(2cosx-3tgx)'=2*(-sinx)-3*\frac{1}{cos^2x}=-2sinx-\frac{3}{cos^2x}\\\\y'=(\frac{x-3}{x+2})'=\frac{(x-3)'(x+2)-(x-3)(x+2)'}{(x+2)^2}=\frac{x+2-(x-3)}{(x+2)^2}=\frac{5}{(x+2)^2}$