Question

Ребята , пожалуйста помогите!!!! срочно!

Answer 1

SinA=CB:AB=15:39 CosA=ac:ab По теореме пифагора найдём АС2=АВ2-СВ2=1521-225=1296=36 Cosa=36:39=12/13 Tga=cb:ab=15:36=5/12 ctgA=cb:ac=36:15 sinB=ac:ab=36:39=12/13 cosb=cb:ab=15:39=5/13 tgB=ac:cb=36:15=13/5 ctgB=cb/ac=15:36=5/13

Answer 2

Аналогично предыдущим задачам
AB = 39, BC = 15, < С = 90 гр.
AB - гипотенуза, BC - катет. Второй катет
AC^2 = AB^2 - BC^2 = 39^2 - 15^2 = 1521 - 225 = 1296 = 36^2
AC = 36
sin A = BC/AB = 15/39 = 5/13
cos A = AC/AB = 36/39 = 12/13
tg A = BC/AC = 15/36 = 5/12
ctg A = 1/tg A = 12/5
sin B = AC/AB = 36/39 = 12/13
cos B = BC/AB = 15/39 = 5/13
tg B = AC/BC = 36/15 = 12/5
ctg B = 1/tg B = 5/12