Question

Вычислите:

1. arccos1 - arccos (-1/2) + arccos √3/2

2. arccos (sin п/6)
3. tg (arccos (-√2/2))

Answer 1

$arccos 1-arccos(-1/2)+arccos( sqrt{3}/2)=0- frac{2 pi }{3} + frac{pi}{6}=-frac{pi }{2}$

$arccos(sin frac{pi}{6})=arccos(1/2) = frac{pi}{3}$

$tg(arccos(-sqrt{2}/2))=tg( frac{3 pi }{4} )=-1$