Question

Задания во вкладках................

Answer 1

$y= frac{ln x}{x^3} \ y'= frac{(ln x)'x^3-(x^3)'ln x}{(x^3)^2} =frac{ frac{1}{x}cdot x^3-3x^2ln x}{x^6} = frac{ x^2-3x^2ln x}{x^6} =frac{ 1-3ln x}{x^4} \ y'(2)=frac{ 1-3ln 2}{2^4} =frac{ 1-3ln 2}{16}$