Question

Упростите выражение ( sin4a+cos4a·ctg2a )/(sin4a-cos4a·tg2a )

Answer 1

$frac{sin 4 alpha+cos 4alphacdot ctg2alpha }{sin4alpha-cos 4alphacdot tg2alpha} = frac{2sin2alphacos2alpha+(1-2sin^22alpha)cdot frac{cos 2alpha}{sin2alpha} }{2sin2alphacos2alpha-(2cos^22alpha-1)cdot frac{sin2alpha}{cos2alpha} } = \ \ = frac{2sin2alphacos2alpha+ frac{cos2alpha}{sin2alpha}-2sin2alphacos2alpha }{2sin2alphacos2alpha-2cos2alphasin2alpha+ frac{sin2alpha}{cos2alpha} } =dfrac{ frac{cos2alpha}{sin2alpha} }{ frac{sin2alpha}{cos2alpha} }= frac{cos^22alpha}{sin^22alpha} =ctg^22alpha$

Answer 2

ай да

Answer 3

ну ответ у меня также)