Question

люди добрые и неочень!!)хелп!!!!!!!!!!!!!!!!!!!!!!!!

Answer 1

$-x> frac{2x-3}{x}$

 

$frac{2x-3}{x}+x<0|*xneq0$

 

$frac{x^{2}+2x-3}{x}<0$

 

$frac{(x-1)(x+3)}{x}<0$

 

           _                               +                        -                                   +

______________-3_____________0_______________1____________________

 

$(-infty;-3)cup(0;1)$

 

 

 

(2x-5)(x+7)(x+1)>0

2(x-2,5)(x+7)(x+1)>0

 

       -                +                                   -                           +

_______ -7______________ -1_____________ 2,5____________________

 

$(-7;-1)cup(2,5;+infty)$

 

 

$(sqrt{6}-2,5)(7-6x)(2sqrt{7}-5)<0$

 

$sqrt{6}-2,5<0$ ,т.к. $2,5^{2}=6,25$

 

$sqrt{7}-5<0$ , т.к. $5^{2}=25$

 

7-6x=6(7/6 -x)<0

 

        +                              -

------------ 7/6---------------

  -*+*-=+                        -*-*-=-

   

$(7/6;+infty)$