Предмет: Химия, автор: tera123

Определите, какой объем (н.у) хлороводорода образуется при горении 33.6 л водорода в хлоре

Ответы

Автор ответа: NatkaRomashka

0

H2 + Cl2 -> 2HCl
ню(Сl2) = 1,5
ню (HCl) = 3
V(HCl) = 3*22.4 = 67.2

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