Question

найдите корни уравнения:

б)2x^3+x^2+6x+3=0

г)5x^3-x^2+20x-4=0

 

Answer 1

1) (2 * X³ - X²) - (6 * X - 3) = 0
X² * (2 * X - 1) - 3 * (2 * X - 1) = 0
(X² - 3) * (2 * X - 1) = 0
2 * (X - √ 3) * (X + √ 3) * (X - 1/2) = 0
X₁ = - √ 3 X₂ = √ 3 X₃ = 1/2

2) x^2(5x+1)-4(5x+1)

(x^2-4)(5x+1)

x^2-4=0 5x+1=0

x^2=4 5x=-1

x= -2,2 x=-1/5